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# Electric Power is generally estimated in kilowatts (kW). Electric energy is generally estimated in kilowatt-hours (kW·h). For instance, if an electric burden that draws 1.5 kW of electric force is worked for 8 hours, it utilizes 12 kW·h of electric energy. In the United States, a private electric client is charged dependent on the measure of electric energy utilized. On the client charge, the electric utility expresses the measure of electric energy, in kilowatt-hours (kW·h), that the client utilized since the last bill, and the expense of the energy each kilowatt-hour (kW·h).

Climate control system sizes are regularly given as “tons” of cooling, where 1 ton of cooling rises to 12,000 BTU/h (3.5 kW). 1 ton of cooling rises to the measure of force that should be applied constantly over a 24-hour time frame to liquefy 1 ton of ice.

The yearly expense of electric energy devoured by a climate control system might be determined as follows:

(Cost, \$/year) = (unit size, BTU/h) × (hours of the year, h) × (energy cost, \$/kW·h) ÷ (SEER, BTU/W·h) ÷ (1000, W/kW)

Model 1:

A cooling unit appraised at 72,000 BTU/h (21 kW) (6 tons), with a SEER rating of 10, works 1000 hours of the year at an electric energy cost of \$0.12 each kilowatt-hour (kW·h). What is the yearly expense of the electric energy it employments?

(72,000 BTU/h) × (1000 h/year) × (\$0.12/kW·h) ÷ (10 BTU/W·h) ÷ (1000 W/kW) = \$860/year

Model 2.

A home close to Ottawa has a climate control system with a cooling limit of 4 tons and a SEER rating of 10. The unit is worked 120 days every year for 8 hours of the day (960 hours out of each year), and the electric energy cost is \$0.10 each kilowatt-hour. What is its yearly expense of activity as far as electric energy? To start with, we convert huge loads of cooling to BTU/h:

(4 tons) × (12,000 (BTU/h)/ton) = 48,000 BTU/h.

The yearly expense of the electric energy is:

(48,000 BTU/h) × (960 h/year) × (\$0.10/kW·h) ÷ (10 BTU/W·h) ÷ (1000 W/kW) = \$460/year